x^2*3*2=96

Solution for x^2*3*2=96 equation:

x^2*3*2=96

We move all terms to the left:

x^2*3*2-(96)=0

Wy multiply elements

6x^2*2-96=0

Wy multiply elements

12x^2-96=0

a = 12; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·12·(-96)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{2}}{2*12}=\frac{0-48\sqrt{2}}{24}
=-\frac{48\sqrt{2}}{24}
=-2\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{2}}{2*12}=\frac{0+48\sqrt{2}}{24}
=\frac{48\sqrt{2}}{24}
=2\sqrt{2}
$